Evaluate 6-(18-3^2)/(4+(2-3))

$6 - \frac{18 - 3^{2}}{4 + (2 - 3)}$

Step 1

Remove parentheses.

$6 - \frac{18 - 3^{2}}{4 + 2 - 3}$

Step 2

Simplify each term.

Simplify the numerator.

Raise $3$ to the power of $2$ .

$6 - \frac{18 - 1 \cdot 9}{4 + 2 - 3}$

Multiply $- 1$ by $9$ .

$6 - \frac{18 - 9}{4 + 2 - 3}$

Subtract $9$ from $18$ .

$6 - \frac{9}{4 + 2 - 3}$

$6 - \frac{9}{4 + 2 - 3}$

Simplify the denominator.

Add $4$ and $2$ .

$6 - \frac{9}{6 - 3}$

Subtract $3$ from $6$ .

$6 - \frac{9}{3}$

$6 - \frac{9}{3}$

Divide $9$ by $3$ .

$6 - 1 \cdot 3$

Multiply $- 1$ by $3$ .

$6 - 3$

$6 - 3$

Step 3

Subtract $3$ from $6$ .

$3$

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