Evaluate g(-x)=x^3

$g (- x) = x^{3}$

Step 1

Divide each term in $g (- x) = x^{3}$ by $- 1 x$ .

$\frac{g (- x)}{- 1 x} = \frac{x^{3}}{- 1 x}$

Step 2

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{g (x)}{x} = \frac{x^{3}}{- 1 x}$

Cancel the common factor of $x$ .

Cancel the common factor.

$\frac{g x}{x} = \frac{x^{3}}{- 1 x}$

Divide $g$ by $1$ .

$g = \frac{x^{3}}{- 1 x}$

Step 3

Simplify the right side.

Cancel the common factor of $x^{3}$ and $x$ .

Factor $x$ out of $x^{3}$ .

$g = \frac{x \cdot x^{2}}{- 1 x}$

Move the negative one from the denominator of $\frac{x^{2}}{- 1}$ .

$g = - 1 \cdot x^{2}$

Rewrite $- 1 \cdot x^{2}$ as $- x^{2}$ .

$g = - x^{2}$