Evaluate cube root of 2x+3=3

$\sqrt[3]{2 x + 3} = 3$

Step 1

To remove the radical on the left side of the equation, cube both sides of the equation.

${\sqrt[3]{2 x + 3}}^{3} = 3^{3}$

Step 2

Simplify each side of the equation.

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt[3]{2 x + 3}$ as ${(2 x + 3)}^{\frac{1}{3}}$ .

${({(2 x + 3)}^{\frac{1}{3}})}^{3} = 3^{3}$

Simplify the left side.

Simplify ${({(2 x + 3)}^{\frac{1}{3}})}^{3}$ .

Multiply the exponents in ${({(2 x + 3)}^{\frac{1}{3}})}^{3}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

${(2 x + 3)}^{\frac{1}{3} \cdot 3} = 3^{3}$

Cancel the common factor of $3$ .

Cancel the common factor.

${(2 x + 3)}^{\frac{1}{3} \cdot 3} = 3^{3}$

Rewrite the expression.

${(2 x + 3)}^{1} = 3^{3}$

Simplify.

$2 x + 3 = 3^{3}$

Simplify the right side.

Raise $3$ to the power of $3$ .

$2 x + 3 = 27$

Step 3

Solve for $x$ .

Move all terms not containing $x$ to the right side of the equation.

Subtract $3$ from both sides of the equation.

$2 x = 27 - 3$

Subtract $3$ from $27$ .

$2 x = 24$

Divide each term in $2 x = 24$ by $2$ and simplify.

Divide each term in $2 x = 24$ by $2$ .

$\frac{2 x}{2} = \frac{24}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x}{2} = \frac{24}{2}$

Divide $x$ by $1$ .

$x = \frac{24}{2}$

Simplify the right side.

Divide $24$ by $2$ .

$x = 12$