Evaluate f(x) = square root of 3-3

$f (x) = \sqrt{3 - 3}$

Step 1

Simplify $\sqrt{3 - 3}$ .

Start simplifying.

$f (x) = 0 + 0 + \sqrt{3 - 3}$

Simplify by adding zeros.

$f (x) = \sqrt{3 - 3}$

Subtract $3$ from $3$ .

$f (x) = \sqrt{0}$

Rewrite $0$ as $0^{2}$ .

$f (x) = \sqrt{0^{2}}$

Pull terms out from under the radical, assuming positive real numbers.

$f (x) = 0$

Step 2

Subtract $f (x)$ from both sides of the equation.

$0 = - f (x)$

Step 3

Rewrite the equation as $- f (x) = 0$ .

$- f (x) = 0$