Evaluate sixth root of 16

$\sqrt[6]{16}$

Step 1

Rewrite $16$ as $4^{2}$ .

$\sqrt[6]{4^{2}}$

Step 2

Rewrite $\sqrt[6]{4^{2}}$ as $\sqrt[3]{\sqrt{4^{2}}}$ .

$\sqrt[3]{\sqrt{4^{2}}}$

Step 3

Pull terms out from under the radical, assuming positive real numbers.

$\sqrt[3]{4}$

Step 4

The result can be shown in multiple forms.

Exact Form:

$\sqrt[3]{4}$

Decimal Form:

$1.58740105 \dots$