Evaluate square root of (x-3)^2-8(x-3)

$\sqrt{{(x - 3)}^{2} - 8 (x - 3)}$

Step 1

Factor $x - 3$ out of ${(x - 3)}^{2} - 8 (x - 3)$ .

Factor $x - 3$ out of ${(x - 3)}^{2}$ .

$\sqrt{(x - 3) (x - 3) - 8 (x - 3)}$

Factor $x - 3$ out of $- 8 (x - 3)$ .

$\sqrt{(x - 3) (x - 3) + (x - 3) \cdot - 8}$

Factor $x - 3$ out of $(x - 3) (x - 3) + (x - 3) \cdot - 8$ .

$\sqrt{(x - 3) (x - 3 - 8)}$

Step 2

Subtract $8$ from $- 3$ .

$\sqrt{(x - 3) (x - 11)}$