Evaluate the Formula y = log base 3 of x+5 , x=27

$y = \log_{3} (x) + 5$ , $x = 27$

Substitute $27$ in for $x$ .

$y = \log_{3} (27) + 5$

Solve for $y$ .

Remove parentheses.

$y = \log_{3} (27) + 5$

Simplify $\log_{3} (27) + 5$ .

Logarithm base $3$ of $27$ is $3$ .

$y = 3 + 5$

Add $3$ and $5$ .

$y = 8$