Evaluate the Function f(3) = square root of 3-3

$f (3) = \sqrt{3 - 3}$

Replace the variable $3$ with $3$ in the expression.

$f (3) = \sqrt{(3) - (3)}$

Simplify the result.

Multiply $- 1$ by $3$ .

$f (3) = \sqrt{3 - 3}$

Subtract $3$ from $3$ .

$f (3) = \sqrt{0}$

Rewrite $0$ as $0^{2}$ .

$f (3) = \sqrt{0^{2}}$

Pull terms out from under the radical, assuming positive real numbers.

$f (3) = 0$

The final answer is $0$ .

$0$