Evaluate the Function h(-8)=(x^2+3x)/(4x+27)

$h (- 8) = \frac{x^{2} + 3 x}{4 x + 27}$

Step 1

Replace the variable $x$ with $- 8$ in the expression.

$h (- 8) = \frac{{(- 8)}^{2} + 3 (- 8)}{4 (- 8) + 27}$

Step 2

Simplify the result.

Simplify the numerator.

Raise $- 8$ to the power of $2$ .

$h (- 8) = \frac{64 + 3 (- 8)}{4 (- 8) + 27}$

Multiply $3$ by $- 8$ .

$h (- 8) = \frac{64 - 24}{4 (- 8) + 27}$

Subtract $24$ from $64$ .

$h (- 8) = \frac{40}{4 (- 8) + 27}$

Simplify the denominator.

Multiply $4$ by $- 8$ .

$h (- 8) = \frac{40}{- 32 + 27}$

Add $- 32$ and $27$ .

$h (- 8) = \frac{40}{- 5}$

Divide $40$ by $- 5$ .

$h (- 8) = - 8$

The final answer is $- 8$ .

$- 8$

Step 3