Expand the Logarithmic Expression log base 2 of 1/16

$\log_{2} (\frac{1}{16})$

Rewrite $\log_{2} (\frac{1}{16})$ as $\log_{2} (1) - \log_{2} (16)$ .

$\log_{2} (1) - \log_{2} (16)$

Logarithm base $2$ of $1$ is $0$ .

$0 - \log_{2} (16)$

Logarithm base $2$ of $16$ is $4$ .

$0 - 1 \cdot 4$

Multiply $- 1$ by $4$ .

$0 - 4$

Subtract $4$ from $0$ .

$- 4$