Expand the Logarithmic Expression log base 5 of 5x^-5

$\log_{5} (5 x^{- 5})$

Step 1

Rewrite $\log_{5} (5 x^{- 5})$ as $\log_{5} (5) + \log_{5} (x^{- 5})$ .

$\log_{5} (5) + \log_{5} (x^{- 5})$

Step 2

Expand $\log_{5} (x^{- 5})$ by moving $- 5$ outside the logarithm.

$\log_{5} (5) - 5 \log_{5} (x)$

Step 3

Logarithm base $5$ of $5$ is $1$ .

$1 - 5 \log_{5} (x)$