Expand the Logarithmic Expression log of 25+( log of 8* log of 16)/( log of 64)

$\log (25) + \frac{\log (8) \cdot \log (16)}{\log (64)}$

Rewrite $\log (25)$ as $\log (5^{2})$ .

$\log (5^{2}) + \frac{\log (8) \cdot \log (16)}{\log (64)}$

Expand $\log (5^{2})$ by moving $2$ outside the logarithm.

$2 \log (5) + \frac{\log (8) \cdot \log (16)}{\log (64)}$

Rewrite $\log (8)$ as $\log (2^{3})$ .

$2 \log (5) + \frac{\log (2^{3}) \cdot \log (16)}{\log (64)}$

Expand $\log (2^{3})$ by moving $3$ outside the logarithm.

$2 \log (5) + \frac{3 \log (2) \cdot \log (16)}{\log (64)}$

Rewrite $\log (16)$ as $\log (2^{4})$ .

$2 \log (5) + \frac{3 \log (2) \cdot \log (2^{4})}{\log (64)}$

Expand $\log (2^{4})$ by moving $4$ outside the logarithm.

$2 \log (5) + \frac{3 \log (2) \cdot (4 \log (2))}{\log (64)}$

Rewrite $\log (64)$ as $\log (2^{6})$ .

$2 \log (5) + \frac{3 \log (2) \cdot (4 \log (2))}{\log (2^{6})}$

Expand $\log (2^{6})$ by moving $6$ outside the logarithm.

$2 \log (5) + \frac{3 \log (2) \cdot (4 \log (2))}{6 \log (2)}$

Cancel the common factor of $3$ and $6$ .

Factor $3$ out of $3 \log (2) \cdot (4 \log (2))$ .

$2 \log (5) + \frac{3 (\log (2) \cdot (4 \log (2)))}{6 \log (2)}$

Cancel the common factors.

Factor $3$ out of $6 \log (2)$ .

$2 \log (5) + \frac{3 (\log (2) \cdot (4 \log (2)))}{3 (2 \log (2))}$

Cancel the common factor.

$2 \log (5) + \frac{3 (\log (2) \cdot (4 \log (2)))}{3 (2 \log (2))}$

Rewrite the expression.

$2 \log (5) + \frac{\log (2) \cdot (4 \log (2))}{2 \log (2)}$

Cancel the common factor of $\log (2)$ .

Cancel the common factor.

$2 \log (5) + \frac{\log (2) \cdot (4 \log (2))}{2 \log (2)}$

Rewrite the expression.

$2 \log (5) + \frac{4 \log (2)}{2}$

Cancel the common factor of $4$ and $2$ .

Factor $2$ out of $4 \log (2)$ .

$2 \log (5) + \frac{2 (2 \log (2))}{2}$

Cancel the common factors.

Factor $2$ out of $2$ .

$2 \log (5) + \frac{2 (2 \log (2))}{2 (1)}$

Cancel the common factor.

$2 \log (5) + \frac{2 (2 \log (2))}{2 \cdot 1}$

Rewrite the expression.

$2 \log (5) + \frac{2 \log (2)}{1}$

Divide $2 \log (2)$ by $1$ .

$2 \log (5) + 2 \log (2)$