Factor 8x^2+24x-80

$8 x^{2} + 24 x - 80$

Step 1

Factor $8$ out of $8 x^{2} + 24 x - 80$ .

Factor $8$ out of $8 x^{2}$ .

$8 (x^{2}) + 24 x - 80$

Factor $8$ out of $24 x$ .

$8 (x^{2}) + 8 (3 x) - 80$

Factor $8$ out of $- 80$ .

$8 x^{2} + 8 (3 x) + 8 \cdot - 10$

Factor $8$ out of $8 x^{2} + 8 (3 x)$ .

$8 (x^{2} + 3 x) + 8 \cdot - 10$

Factor $8$ out of $8 (x^{2} + 3 x) + 8 \cdot - 10$ .

$8 (x^{2} + 3 x - 10)$

Step 2

Factor.

Factor $x^{2} + 3 x - 10$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $- 10$ and whose sum is $3$ .

$- 2, 5$

Write the factored form using these integers.

$8 ((x - 2) (x + 5))$

Remove unnecessary parentheses.

$8 (x - 2) (x + 5)$

Factor 8x^2+24x-80

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