Factor factoring 4x^2+20x+16

factoring $4 x^{2} + 20 x + 16$

Step 1

Factor $4$ out of $4 x^{2} + 20 x + 16$ .

Factor $4$ out of $4 x^{2}$ .

$4 (x^{2}) + 20 x + 16$

Factor $4$ out of $20 x$ .

$4 (x^{2}) + 4 (5 x) + 16$

Factor $4$ out of $16$ .

$4 x^{2} + 4 (5 x) + 4 \cdot 4$

Factor $4$ out of $4 x^{2} + 4 (5 x)$ .

$4 (x^{2} + 5 x) + 4 \cdot 4$

Factor $4$ out of $4 (x^{2} + 5 x) + 4 \cdot 4$ .

$4 (x^{2} + 5 x + 4)$

Step 2

Factor.

Factor $x^{2} + 5 x + 4$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $4$ and whose sum is $5$ .

$1, 4$

Write the factored form using these integers.

$4 ((x + 1) (x + 4))$

Remove unnecessary parentheses.

$4 (x + 1) (x + 4)$

Factor factoring 4x^2+20x+16

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