Find a,b,c x^2-8x+16=0

$x^{2} - 8 x + 16 = 0$

Step 1

Once the quadratic is in standard form, the values of $a$ , $b$ , and $c$ can be found.

$a x^{2} + b x + c$

Step 2

Use the standard form of the equation to find $a$ , $b$ , and $c$ for this quadratic.

$a = 1$ , $b = - 8$ , $c = 16$