Find a,b,c -y^2-16y-64=0

$- y^{2} - 16 y - 64 = 0$

Step 1

Once the quadratic is in standard form, the values of $a$ , $b$ , and $c$ can be found.

$a y^{2} + b y + c$

Step 2

Use the standard form of the equation to find $a$ , $b$ , and $c$ for this quadratic.

$a = - 1$ , $b = - 16$ , $c = - 64$