Find All Complex Solutions -2z+10+7z=16z+7

$- 2 z + 10 + 7 z = 16 z + 7$

Step 1

Add $- 2 z$ and $7 z$ .

$5 z + 10 = 16 z + 7$

Step 2

Move all terms containing $z$ to the left side of the equation.

Subtract $16 z$ from both sides of the equation.

$5 z + 10 - 16 z = 7$

Subtract $16 z$ from $5 z$ .

$- 11 z + 10 = 7$

Step 3

Move all terms not containing $z$ to the right side of the equation.

Subtract $10$ from both sides of the equation.

$- 11 z = 7 - 10$

Subtract $10$ from $7$ .

$- 11 z = - 3$

Step 4

Divide each term in $- 11 z = - 3$ by $- 11$ and simplify.

Divide each term in $- 11 z = - 3$ by $- 11$ .

$\frac{- 11 z}{- 11} = \frac{- 3}{- 11}$

Simplify the left side.

Cancel the common factor of $- 11$ .

Cancel the common factor.

$\frac{- 11 z}{- 11} = \frac{- 3}{- 11}$

Divide $z$ by $1$ .

$z = \frac{- 3}{- 11}$

Simplify the right side.

Dividing two negative values results in a positive value.

$z = \frac{3}{11}$