Find All Complex Solutions square root of 2x+8-6=-4

$\sqrt{2 x + 8} - 6 = - 4$

Move all terms not containing $\sqrt{2 x + 8}$ to the right side of the equation.

Add $6$ to both sides of the equation.

$\sqrt{2 x + 8} = - 4 + 6$

Add $- 4$ and $6$ .

$\sqrt{2 x + 8} = 2$

To remove the radical on the left side of the equation, square both sides of the equation.

${\sqrt{2 x + 8}}^{2} = 2^{2}$

Simplify each side of the equation.

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{2 x + 8}$ as ${(2 x + 8)}^{\frac{1}{2}}$ .

${({(2 x + 8)}^{\frac{1}{2}})}^{2} = 2^{2}$

Simplify the left side.

Simplify ${({(2 x + 8)}^{\frac{1}{2}})}^{2}$ .

Multiply the exponents in ${({(2 x + 8)}^{\frac{1}{2}})}^{2}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

${(2 x + 8)}^{\frac{1}{2} \cdot 2} = 2^{2}$

Cancel the common factor of $2$ .

Cancel the common factor.

${(2 x + 8)}^{\frac{1}{2} \cdot 2} = 2^{2}$

Rewrite the expression.

${(2 x + 8)}^{1} = 2^{2}$

Simplify.

$2 x + 8 = 2^{2}$

Simplify the right side.

Raise $2$ to the power of $2$ .

$2 x + 8 = 4$

Solve for $x$ .

Move all terms not containing $x$ to the right side of the equation.

Subtract $8$ from both sides of the equation.

$2 x = 4 - 8$

Subtract $8$ from $4$ .

$2 x = - 4$

Divide each term in $2 x = - 4$ by $2$ and simplify.

Divide each term in $2 x = - 4$ by $2$ .

$\frac{2 x}{2} = \frac{- 4}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x}{2} = \frac{- 4}{2}$

Divide $x$ by $1$ .

$x = \frac{- 4}{2}$

Simplify the right side.

Divide $- 4$ by $2$ .

$x = - 2$