Find All Complex Solutions square root of 4x=x-3

$\sqrt{4 x} = x - 3$

Step 1

Move all the expressions to the left side of the equation.

Subtract $x$ from both sides of the equation.

$\sqrt{4 x} - x = - 3$

Add $3$ to both sides of the equation.

$\sqrt{4 x} - x + 3 = 0$

Step 2

Simplify each term.

Rewrite $4$ as $2^{2}$ .

$\sqrt{2^{2} x} - x + 3 = 0$

Pull terms out from under the radical.

$2 \sqrt{x} - x + 3 = 0$

Step 3

Factor the left side of the equation.

Factor $- 1$ out of $2 \sqrt{x} - x + 3$ .

Reorder $2 \sqrt{x}$ and $- x$ .

$- x + 2 \sqrt{x} + 3 = 0$

Factor $- 1$ out of $- x$ .

$- (x) + 2 \sqrt{x} + 3 = 0$

Factor $- 1$ out of $2 \sqrt{x}$ .

$- (x) - (- 2 \sqrt{x}) + 3 = 0$

Rewrite $3$ as $- 1 (- 3)$ .

$- (x) - (- 2 \sqrt{x}) - 1 \cdot - 3 = 0$

Factor $- 1$ out of $- (x) - (- 2 \sqrt{x})$ .

$- (x - 2 \sqrt{x}) - 1 \cdot - 3 = 0$

Factor $- 1$ out of $- (x - 2 \sqrt{x}) - 1 (- 3)$ .

$- (x - 2 \sqrt{x} - 3) = 0$

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{x}$ as $x^{\frac{1}{2}}$ .

$- (x - 2 x^{\frac{1}{2}} - 3) = 0$

Rewrite $x$ as ${(x^{\frac{1}{2}})}^{2}$ .

$- ({(x^{\frac{1}{2}})}^{2} - 2 x^{\frac{1}{2}} - 3) = 0$

Let $u = x^{\frac{1}{2}}$ . Substitute $u$ for all occurrences of $x^{\frac{1}{2}}$ .

$- (u^{2} - 2 u - 3) = 0$

Factor $u^{2} - 2 u - 3$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $- 3$ and whose sum is $- 2$ .

$- 3, 1$

Write the factored form using these integers.

$- ((u - 3) (u + 1)) = 0$

Factor.

Replace all occurrences of $u$ with $x^{\frac{1}{2}}$ .

$- ((x^{\frac{1}{2}} - 3) (x^{\frac{1}{2}} + 1)) = 0$

Remove unnecessary parentheses.

$- (x^{\frac{1}{2}} - 3) (x^{\frac{1}{2}} + 1) = 0$

Step 4

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x^{\frac{1}{2}} - 3 = 0$

$x^{\frac{1}{2}} + 1 = 0$

Step 5

Set $x^{\frac{1}{2}} - 3$ equal to $0$ and solve for $x$ .

Set $x^{\frac{1}{2}} - 3$ equal to $0$ .

$x^{\frac{1}{2}} - 3 = 0$

Solve $x^{\frac{1}{2}} - 3 = 0$ for $x$ .

Add $3$ to both sides of the equation.

$x^{\frac{1}{2}} = 3$

Raise each side of the equation to the power of $2$ to eliminate the fractional exponent on the left side.

${(x^{\frac{1}{2}})}^{2} = 3^{2}$

Simplify the exponent.

Simplify the left side.

Simplify ${(x^{\frac{1}{2}})}^{2}$ .

Multiply the exponents in ${(x^{\frac{1}{2}})}^{2}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$x^{\frac{1}{2} \cdot 2} = 3^{2}$

Cancel the common factor of $2$ .

Cancel the common factor.

$x^{\frac{1}{2} \cdot 2} = 3^{2}$

Rewrite the expression.

$x^{1} = 3^{2}$

Simplify.

$x = 3^{2}$

Simplify the right side.

Raise $3$ to the power of $2$ .

$x = 9$

Step 6

Set $x^{\frac{1}{2}} + 1$ equal to $0$ and solve for $x$ .

Set $x^{\frac{1}{2}} + 1$ equal to $0$ .

$x^{\frac{1}{2}} + 1 = 0$

Solve $x^{\frac{1}{2}} + 1 = 0$ for $x$ .

Subtract $1$ from both sides of the equation.

$x^{\frac{1}{2}} = - 1$

Raise each side of the equation to the power of $2$ to eliminate the fractional exponent on the left side.

${(x^{\frac{1}{2}})}^{2} = {(- 1)}^{2}$

Simplify the exponent.

Simplify the left side.

Simplify ${(x^{\frac{1}{2}})}^{2}$ .

Multiply the exponents in ${(x^{\frac{1}{2}})}^{2}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$x^{\frac{1}{2} \cdot 2} = {(- 1)}^{2}$

Cancel the common factor of $2$ .

Cancel the common factor.

$x^{\frac{1}{2} \cdot 2} = {(- 1)}^{2}$

Rewrite the expression.

$x^{1} = {(- 1)}^{2}$

Simplify.

$x = {(- 1)}^{2}$

Simplify the right side.

Raise $- 1$ to the power of $2$ .

$x = 1$

Step 7

The final solution is all the values that make $- (x^{\frac{1}{2}} - 3) (x^{\frac{1}{2}} + 1) = 0$ true.

$x = 9, 1$

Find All Complex Solutions square root of 4x=x-3

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