Find the Perpendicular Line through (-2,0) , perpendicular to 8x-3y=7

through $(- 2, 0)$ , perpendicular to $8 x - 3 y = 7$

Solve $8 x - 3 y = 7$ .

Subtract $8 x$ from both sides of the equation.

$- 3 y = 7 - 8 x$

Divide each term in $- 3 y = 7 - 8 x$ by $- 3$ and simplify.

Divide each term in $- 3 y = 7 - 8 x$ by $- 3$ .

$\frac{- 3 y}{- 3} = \frac{7}{- 3} + \frac{- 8 x}{- 3}$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 y}{- 3} = \frac{7}{- 3} + \frac{- 8 x}{- 3}$

Divide $y$ by $1$ .

$y = \frac{7}{- 3} + \frac{- 8 x}{- 3}$

Simplify the right side.

Simplify each term.

Move the negative in front of the fraction.

$y = - \frac{7}{3} + \frac{- 8 x}{- 3}$

Dividing two negative values results in a positive value.

$y = - \frac{7}{3} + \frac{8 x}{3}$

Find the slope when $y = - \frac{7}{3} + \frac{8 x}{3}$ .

Rewrite in slope-intercept form.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Reorder $- \frac{7}{3}$ and $\frac{8 x}{3}$ .

$y = \frac{8 x}{3} - \frac{7}{3}$

Reorder terms.

$y = \frac{8}{3} x - \frac{7}{3}$

Using the slope-intercept form, the slope is $\frac{8}{3}$ .

$m = \frac{8}{3}$

The equation of a perpendicular line must have a slope that is the negative reciprocal of the original slope.

$m_{perpendicular} = - \frac{1}{\frac{8}{3}}$

Simplify $- \frac{1}{\frac{8}{3}}$ to find the slope of the perpendicular line.

Multiply the numerator by the reciprocal of the denominator.

$m_{perpendicular} = - (1 (\frac{3}{8}))$

Multiply $\frac{3}{8}$ by $1$ .

$m_{perpendicular} = - \frac{3}{8}$

Find the equation of the perpendicular line using the point-slope formula.

Use the slope $- \frac{3}{8}$ and a given point $(- 2, 0)$ to substitute for $x_{1}$ and $y_{1}$ in the point-slope form $y - y_{1} = m (x - x_{1})$ , which is derived from the slope equation $m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ .

$y - (0) = - \frac{3}{8} \cdot (x - (- 2))$

Simplify the equation and keep it in point-slope form.

$y + 0 = - \frac{3}{8} \cdot (x + 2)$

Write in $y = m x + b$ form.

Solve for $y$ .

Add $y$ and $0$ .

$y = - \frac{3}{8} \cdot (x + 2)$

Simplify $- \frac{3}{8} \cdot (x + 2)$ .

Simplify terms.

Apply the distributive property.

$y = - \frac{3}{8} x - \frac{3}{8} \cdot 2$

Combine $x$ and $\frac{3}{8}$ .

$y = - \frac{x \cdot 3}{8} - \frac{3}{8} \cdot 2$

Cancel the common factor of $2$ .

Move the leading negative in $- \frac{3}{8}$ into the numerator.

$y = - \frac{x \cdot 3}{8} + \frac{- 3}{8} \cdot 2$

Factor $2$ out of $8$ .

$y = - \frac{x \cdot 3}{8} + \frac{- 3}{2 (4)} \cdot 2$

Cancel the common factor.

$y = - \frac{x \cdot 3}{8} + \frac{- 3}{2 \cdot 4} \cdot 2$

Rewrite the expression.

$y = - \frac{x \cdot 3}{8} + \frac{- 3}{4}$

Simplify each term.

Move $3$ to the left of $x$ .

$y = - \frac{3 \cdot x}{8} + \frac{- 3}{4}$

Move the negative in front of the fraction.

$y = - \frac{3 x}{8} - \frac{3}{4}$

Reorder terms.

$y = - (\frac{3}{8} x) - \frac{3}{4}$

Remove parentheses.

$y = - \frac{3}{8} x - \frac{3}{4}$

Find the Perpendicular Line through (-2,0) , perpendicular to 8x-3y=7

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