Find All Complex Solutions x = square root of -3x+40

$x = \sqrt{- 3 x + 40}$

Step 1

Since the radical is on the right side of the equation, switch the sides so it is on the left side of the equation.

$\sqrt{- 3 x + 40} = x$

Step 2

To remove the radical on the left side of the equation, square both sides of the equation.

${\sqrt{- 3 x + 40}}^{2} = x^{2}$

Step 3

Simplify each side of the equation.

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{- 3 x + 40}$ as ${(- 3 x + 40)}^{\frac{1}{2}}$ .

${({(- 3 x + 40)}^{\frac{1}{2}})}^{2} = x^{2}$

Simplify the left side.

Simplify ${({(- 3 x + 40)}^{\frac{1}{2}})}^{2}$ .

Multiply the exponents in ${({(- 3 x + 40)}^{\frac{1}{2}})}^{2}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

${(- 3 x + 40)}^{\frac{1}{2} \cdot 2} = x^{2}$

Cancel the common factor of $2$ .

Cancel the common factor.

${(- 3 x + 40)}^{\frac{1}{2} \cdot 2} = x^{2}$

Rewrite the expression.

${(- 3 x + 40)}^{1} = x^{2}$

Simplify.

$- 3 x + 40 = x^{2}$

Step 4

Solve for $x$ .

Subtract $x^{2}$ from both sides of the equation.

$- 3 x + 40 - x^{2} = 0$

Factor the left side of the equation.

Factor $- 1$ out of $- 3 x + 40 - x^{2}$ .

Reorder the expression.

Move $40$ .

$- 3 x - x^{2} + 40 = 0$

Reorder $- 3 x$ and $- x^{2}$ .

$- x^{2} - 3 x + 40 = 0$

Factor $- 1$ out of $- x^{2}$ .

$- (x^{2}) - 3 x + 40 = 0$

Factor $- 1$ out of $- 3 x$ .

$- (x^{2}) - (3 x) + 40 = 0$

Rewrite $40$ as $- 1 (- 40)$ .

$- (x^{2}) - (3 x) - 1 \cdot - 40 = 0$

Factor $- 1$ out of $- (x^{2}) - (3 x)$ .

$- (x^{2} + 3 x) - 1 \cdot - 40 = 0$

Factor $- 1$ out of $- (x^{2} + 3 x) - 1 (- 40)$ .

$- (x^{2} + 3 x - 40) = 0$

Factor.

Factor $x^{2} + 3 x - 40$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $- 40$ and whose sum is $3$ .

$- 5, 8$

Write the factored form using these integers.

$- ((x - 5) (x + 8)) = 0$

Remove unnecessary parentheses.

$- (x - 5) (x + 8) = 0$

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x - 5 = 0$

$x + 8 = 0$

Set $x - 5$ equal to $0$ and solve for $x$ .

Set $x - 5$ equal to $0$ .

$x - 5 = 0$

Add $5$ to both sides of the equation.

$x = 5$

Set $x + 8$ equal to $0$ and solve for $x$ .

Set $x + 8$ equal to $0$ .

$x + 8 = 0$

Subtract $8$ from both sides of the equation.

$x = - 8$

The final solution is all the values that make $- (x - 5) (x + 8) = 0$ true.

$x = 5, - 8$

Step 5

Exclude the solutions that do not make $x = \sqrt{- 3 x + 40}$ true.

$x = 5$

Find All Complex Solutions x = square root of -3x+40

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