Find Any Equation Perpendicular to the Line 10x-11y=1

$10 x - 11 y = 1$

Step 1

Choose a point that the perpendicular line will pass through.

$(0, 0)$

Step 2

Solve $10 x - 11 y = 1$ .

Subtract $10 x$ from both sides of the equation.

$- 11 y = 1 - 10 x$

Divide each term in $- 11 y = 1 - 10 x$ by $- 11$ and simplify.

Divide each term in $- 11 y = 1 - 10 x$ by $- 11$ .

$\frac{- 11 y}{- 11} = \frac{1}{- 11} + \frac{- 10 x}{- 11}$

Simplify the left side.

Cancel the common factor of $- 11$ .

Cancel the common factor.

$\frac{- 11 y}{- 11} = \frac{1}{- 11} + \frac{- 10 x}{- 11}$

Divide $y$ by $1$ .

$y = \frac{1}{- 11} + \frac{- 10 x}{- 11}$

Simplify the right side.

Simplify each term.

Move the negative in front of the fraction.

$y = - \frac{1}{11} + \frac{- 10 x}{- 11}$

Dividing two negative values results in a positive value.

$y = - \frac{1}{11} + \frac{10 x}{11}$

Step 3

Find the slope when $y = - \frac{1}{11} + \frac{10 x}{11}$ .

Rewrite in slope-intercept form.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Reorder $- \frac{1}{11}$ and $\frac{10 x}{11}$ .

$y = \frac{10 x}{11} - \frac{1}{11}$

Reorder terms.

$y = \frac{10}{11} x - \frac{1}{11}$

Using the slope-intercept form, the slope is $\frac{10}{11}$ .

$m = \frac{10}{11}$

Step 4

The equation of a perpendicular line must have a slope that is the negative reciprocal of the original slope.

$m_{perpendicular} = - \frac{1}{\frac{10}{11}}$

Step 5

Simplify $- \frac{1}{\frac{10}{11}}$ to find the slope of the perpendicular line.

Multiply the numerator by the reciprocal of the denominator.

$m_{perpendicular} = - (1 (\frac{11}{10}))$

Multiply $\frac{11}{10}$ by $1$ .

$m_{perpendicular} = - \frac{11}{10}$

Step 6

Find the equation of the perpendicular line using the point-slope formula.

Use the slope $- \frac{11}{10}$ and a given point $(0, 0)$ to substitute for $x_{1}$ and $y_{1}$ in the point-slope form $y - y_{1} = m (x - x_{1})$ , which is derived from the slope equation $m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ .

$y - (0) = - \frac{11}{10} \cdot (x - (0))$

Simplify the equation and keep it in point-slope form.

$y + 0 = - \frac{11}{10} \cdot (x + 0)$

Step 7

Write in $y = m x + b$ form.

Solve for $y$ .

Add $y$ and $0$ .

$y = - \frac{11}{10} \cdot (x + 0)$

Simplify $- \frac{11}{10} \cdot (x + 0)$ .

Add $x$ and $0$ .

$y = - \frac{11}{10} \cdot x$

Combine $x$ and $\frac{11}{10}$ .

$y = - \frac{x \cdot 11}{10}$

Move $11$ to the left of $x$ .

$y = - \frac{11 x}{10}$

Reorder terms.

$y = - (\frac{11}{10} x)$

Remove parentheses.

$y = - \frac{11}{10} x$

Step 8

Find Any Equation Perpendicular to the Line 10x-11y=1

Related Questions

Support LCMGCF.com by disabling your adblocker.