Find g(f(x)) f(x)=x^3-9 g(x) = cube root of x+9

$f (x) = x^{3} - 9$ $g (x) = \sqrt[3]{x + 9}$

Step 1

Set up the composite result function.

$g (f (x))$

Step 2

Evaluate $g (x^{3} - 9)$ by substituting in the value of $f$ into $g$ .

$g (x^{3} - 9) = \sqrt[3]{(x^{3} - 9) + 9}$

Step 3

Add $- 9$ and $9$ .

$g (x^{3} - 9) = \sqrt[3]{x^{3} + 0}$

Step 4

Add $x^{3}$ and $0$ .

$g (x^{3} - 9) = \sqrt[3]{x^{3}}$

Step 5

Pull terms out from under the radical, assuming real numbers.

$g (x^{3} - 9) = x$