Find the 5th Term 3 , 15 , 27 , 39

$3$ , $15$ , $27$ , $39$

Step 1

This is an arithmetic sequence since there is a common difference between each term. In this case, adding $12$ to the previous term in the sequence gives the next term. In other words, $a_{n} = a_{1} + d (n - 1)$ .

Arithmetic Sequence: $d = 12$

Step 2

This is the formula of an arithmetic sequence.

$a_{n} = a_{1} + d (n - 1)$

Step 3

Substitute in the values of $a_{1} = 3$ and $d = 12$ .

$a_{n} = 3 + 12 (n - 1)$

Step 4

Simplify each term.

Apply the distributive property.

$a_{n} = 3 + 12 n + 12 \cdot - 1$

Multiply $12$ by $- 1$ .

$a_{n} = 3 + 12 n - 12$

Step 5

Subtract $12$ from $3$ .

$a_{n} = 12 n - 9$

Step 6

Substitute in the value of $n$ to find the $n$ th term.

$a_{5} = 12 (5) - 9$

Step 7

Multiply $12$ by $5$ .

$a_{5} = 60 - 9$

Step 8

Subtract $9$ from $60$ .

$a_{5} = 51$

Find the 5th Term 3 , 15 , 27 , 39

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