Find the Axis of Symmetry f(x)=-(x^2+2x-3)

$f (x) = - (x^{2} + 2 x - 3)$

Write $f (x) = - (x^{2} + 2 x - 3)$ as an equation.

$y = - (x^{2} + 2 x - 3)$

Rewrite the equation in vertex form.

Simplify $- (x^{2} + 2 x - 3)$ .

Apply the distributive property.

$y = - x^{2} - (2 x) - - 3$

Simplify.

Multiply $2$ by $- 1$ .

$y = - x^{2} - 2 x - - 3$

Multiply $- 1$ by $- 3$ .

$y = - x^{2} - 2 x + 3$

Complete the square for $- x^{2} - 2 x + 3$ .

Use the form $a x^{2} + b x + c$ , to find the values of $a$ , $b$ , and $c$ .

$a = - 1$

$b = - 2$

$c = 3$

Consider the vertex form of a parabola.

$a {(x + d)}^{2} + e$

Find the value of $d$ using the formula $d = \frac{b}{2 a}$ .

Substitute the values of $a$ and $b$ into the formula $d = \frac{b}{2 a}$ .

$d = \frac{- 2}{2 \cdot - 1}$

Simplify the right side.

Cancel the common factor of $- 2$ and $2$ .

Factor $2$ out of $- 2$ .

$d = \frac{2 \cdot - 1}{2 \cdot - 1}$

Move the negative one from the denominator of $\frac{- 1}{- 1}$ .

$d = - 1 \cdot - 1$

Rewrite $- 1 \cdot - 1$ as $- - 1$ .

$d = - - 1$

Multiply $- 1$ by $- 1$ .

$d = 1$

Find the value of $e$ using the formula $e = c - \frac{b^{2}}{4 a}$ .

Substitute the values of $c$ , $b$ and $a$ into the formula $e = c - \frac{b^{2}}{4 a}$ .

$e = 3 - \frac{{(- 2)}^{2}}{4 \cdot - 1}$

Simplify the right side.

Simplify each term.

Raise $- 2$ to the power of $2$ .

$e = 3 - \frac{4}{4 \cdot - 1}$

Multiply $4$ by $- 1$ .

$e = 3 - \frac{4}{- 4}$

Divide $4$ by $- 4$ .

$e = 3 - - 1$

Multiply $- 1$ by $- 1$ .

$e = 3 + 1$

Add $3$ and $1$ .

$e = 4$

Substitute the values of $a$ , $d$ , and $e$ into the vertex form $- {(x + 1)}^{2} + 4$ .

$- {(x + 1)}^{2} + 4$

Set $y$ equal to the new right side.

$y = - {(x + 1)}^{2} + 4$

Use the vertex form, $y = a {(x - h)}^{2} + k$ , to determine the values of $a$ , $h$ , and $k$ .

$a = - 1$

$h = - 1$

$k = 4$

Since the value of $a$ is negative, the parabola opens down.

Opens Down

Find the vertex $(h, k)$ .

$(- 1, 4)$

Find $p$ , the distance from the vertex to the focus.

Find the distance from the vertex to a focus of the parabola by using the following formula.

$\frac{1}{4 a}$

Substitute the value of $a$ into the formula.

$\frac{1}{4 \cdot - 1}$

Cancel the common factor of $1$ and $- 1$ .

Rewrite $1$ as $- 1 (- 1)$ .

$\frac{- 1 (- 1)}{4 \cdot - 1}$

Move the negative in front of the fraction.

$- \frac{1}{4}$

Find the focus.

The focus of a parabola can be found by adding $p$ to the y-coordinate $k$ if the parabola opens up or down.

$(h, k + p)$

Substitute the known values of $h$ , $p$ , and $k$ into the formula and simplify.

$(- 1, \frac{15}{4})$

Find the axis of symmetry by finding the line that passes through the vertex and the focus.

$x = - 1$

Find the Axis of Symmetry f(x)=-(x^2+2x-3)

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