Find the Second Term a_n=2n^2+3

$a_{n} = 2 n^{2} + 3$

Step 1

Substitute in the value of $n$ to find the $n$ th term.

$a_{2} = 2 {(2)}^{2} + 3$

Step 2

Simplify each term.

Multiply $2$ by ${(2)}^{2}$ by adding the exponents.

Multiply $2$ by ${(2)}^{2}$ .

Raise $2$ to the power of $1$ .

$a_{2} = 2 {(2)}^{2} + 3$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$a_{2} = 2^{1 + 2} + 3$

Add $1$ and $2$ .

$a_{2} = 2^{3} + 3$

Raise $2$ to the power of $3$ .

$a_{2} = 8 + 3$

Step 3

Add $8$ and $3$ .

$a_{2} = 11$