Find the Bounds of the Zeros (x^3+8x^2-3x-90)÷(x+5)

$(x^{3} + 8 x^{2} - 3 x - 90) \div (x + 5)$

Step 1

Write $(x^{3} + 8 x^{2} - 3 x - 90) \div (x + 5)$ as a function.

$f (x) = (x^{3} + 8 x^{2} - 3 x - 90) \div (x + 5)$

Step 2

Check the leading coefficient of the function. This number is the coefficient of the expression with the largest degree.

Largest Degree: $- 1$

Leading Coefficient: $1$

Step 3

Create a list of the coefficients of the function except the leading coefficient of $1$ .

$0$

Step 4

There will be two bound options, $b_{1}$ and $b_{2}$ , the smaller of which is the answer. To calculate the first bound option, find the absolute value of the largest coefficient from the list of coefficients. Then add $1$ .

Arrange the terms in ascending order.

$b_{1} = 0$

Add $0$ and $1$ .

$b_{1} = 1$

Step 5

To calculate the second bound option, sum the absolute values of the coefficients from the list of coefficients. If the sum is greater than $1$ , use that number. If not, use $1$ .

Arrange the terms in ascending order.

$b_{2} = 0, 1$

The maximum value is the largest value in the arranged data set.

$b_{2} = 1$

Step 6

The bound options are the same.

Bound: $1$

Step 7

Every real root on $f (x) = (x^{3} + 8 x^{2} - 3 x - 90) \div (x + 5)$ lies between $- 1$ and $1$ .

$- 1$ and $1$

Find the Bounds of the Zeros (x^3+8x^2-3x-90)÷(x+5)

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