Find the Discriminant 11x^2-16x+6=0

$11 x^{2} - 16 x + 6 = 0$

Step 1

The discriminant of a quadratic is the expression inside the radical of the quadratic formula.

$b^{2} - 4 (a c)$

Step 2

Substitute in the values of $a$ , $b$ , and $c$ .

${(- 16)}^{2} - 4 (11 \cdot 6)$

Step 3

Evaluate the result to find the discriminant.

Simplify each term.

Raise $- 16$ to the power of $2$ .

$256 - 4 (11 \cdot 6)$

Multiply $- 4 (11 \cdot 6)$ .

Multiply $11$ by $6$ .

$256 - 4 \cdot 66$

Multiply $- 4$ by $66$ .

$256 - 264$

Subtract $264$ from $256$ .

$- 8$