Find the Discriminant 3-4x=-6x^2

$3 - 4 x = - 6 x^{2}$

Step 1

Add $6 x^{2}$ to both sides of the equation.

$3 - 4 x + 6 x^{2} = 0$

Step 2

The discriminant of a quadratic is the expression inside the radical of the quadratic formula.

$b^{2} - 4 (a c)$

Step 3

Substitute in the values of $a$ , $b$ , and $c$ .

${(- 4)}^{2} - 4 (6 \cdot 3)$

Step 4

Evaluate the result to find the discriminant.

Simplify each term.

Raise $- 4$ to the power of $2$ .

$16 - 4 (6 \cdot 3)$

Multiply $- 4 (6 \cdot 3)$ .

Multiply $6$ by $3$ .

$16 - 4 \cdot 18$

Multiply $- 4$ by $18$ .

$16 - 72$

Subtract $72$ from $16$ .

$- 56$