Find the Discriminant x^2-18x+45=-4x

$x^{2} - 18 x + 45 = - 4 x$

Move all terms to the left side of the equation and simplify.

Add $4 x$ to both sides of the equation.

$x^{2} - 18 x + 45 + 4 x = 0$

Add $- 18 x$ and $4 x$ .

$x^{2} - 14 x + 45 = 0$

The discriminant of a quadratic is the expression inside the radical of the quadratic formula.

$b^{2} - 4 (a c)$

Substitute in the values of $a$ , $b$ , and $c$ .

${(- 14)}^{2} - 4 (1 \cdot 45)$

Evaluate the result to find the discriminant.

Simplify each term.

Raise $- 14$ to the power of $2$ .

$196 - 4 (1 \cdot 45)$

Multiply $45$ by $1$ .

$196 - 4 \cdot 45$

Multiply $- 4$ by $45$ .

$196 - 180$

Subtract $180$ from $196$ .

$16$