Find the Roots (Zeros) f(x)=x^4-4x^3+x^2-1

$f (x) = x^{4} - 4 x^{3} + x^{2} - 1$

Step 1

Set $x^{4} - 4 x^{3} + x^{2} - 1$ equal to $0$ .

$x^{4} - 4 x^{3} + x^{2} - 1 = 0$

Step 2

Graph each side of the equation. The solution is the x-value of the point of intersection.

$x \approx - 0.53875199, 3.75243229$

Step 3