Find the Domain and Range f(x)=-3+1/2 square root of x-4

$f (x) = - 3 + \frac{1}{2} \sqrt{x - 4}$

Set the radicand in $\sqrt{x - 4}$ greater than or equal to $0$ to find where the expression is defined.

$x - 4 \geq 0$

Add $4$ to both sides of the inequality.

$x \geq 4$

The domain is all values of $x$ that make the expression defined.

Interval Notation:

$[4, \infty)$

Set-Builder Notation:

${x | x \geq 4}$

The range is the set of all valid $y$ values. Use the graph to find the range.

Interval Notation:

$[- 3, \infty)$

Set-Builder Notation:

${y | y \geq - 3}$

Determine the domain and range.

Domain: $[4, \infty), {x | x \geq 4}$

Range: $[- 3, \infty), {y | y \geq - 3}$