Find the Domain and Range y = square root of -x+3-4

$y = \sqrt{- x + 3} - 4$

Step 1

Set the radicand in $\sqrt{- x + 3}$ greater than or equal to $0$ to find where the expression is defined.

$- x + 3 \geq 0$

Step 2

Solve for $x$ .

Subtract $3$ from both sides of the inequality.

$- x \geq - 3$

Divide each term in $- x \geq - 3$ by $- 1$ and simplify.

Divide each term in $- x \geq - 3$ by $- 1$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- x}{- 1} \leq \frac{- 3}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{x}{1} \leq \frac{- 3}{- 1}$

Divide $x$ by $1$ .

$x \leq \frac{- 3}{- 1}$

Simplify the right side.

Divide $- 3$ by $- 1$ .

$x \leq 3$

Step 3

The domain is all values of $x$ that make the expression defined.

Interval Notation:

$(- \infty, 3]$

Set-Builder Notation:

${x | x \leq 3}$

Step 4

The range is the set of all valid $y$ values. Use the graph to find the range.

Interval Notation:

$[- 4, \infty)$

Set-Builder Notation:

${y | y \geq - 4}$

Step 5

Determine the domain and range.

Domain: $(- \infty, 3], {x | x \leq 3}$

Range: $[- 4, \infty), {y | y \geq - 4}$

Step 6

Find the Domain and Range y = square root of -x+3-4

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