Find the Domain square root of 8-2x

$\sqrt{8 - 2 x}$

Step 1

Set the radicand in $\sqrt{8 - 2 x}$ greater than or equal to $0$ to find where the expression is defined.

$8 - 2 x \geq 0$

Step 2

Solve for $x$ .

Subtract $8$ from both sides of the inequality.

$- 2 x \geq - 8$

Divide each term in $- 2 x \geq - 8$ by $- 2$ and simplify.

Divide each term in $- 2 x \geq - 8$ by $- 2$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- 2 x}{- 2} \leq \frac{- 8}{- 2}$

Simplify the left side.

Cancel the common factor of $- 2$ .

Cancel the common factor.

$\frac{- 2 x}{- 2} \leq \frac{- 8}{- 2}$

Divide $x$ by $1$ .

$x \leq \frac{- 8}{- 2}$

Simplify the right side.

Divide $- 8$ by $- 2$ .

$x \leq 4$

Step 3

The domain is all values of $x$ that make the expression defined.

Interval Notation:

$(- \infty, 4]$

Set-Builder Notation:

${x | x \leq 4}$

Step 4

Find the Domain square root of 8-2x

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