Find the Domain (x^2)/(x-8)

$\frac{x^{2}}{x - 8}$

Step 1

Set the denominator in $\frac{x^{2}}{x - 8}$ equal to $0$ to find where the expression is undefined.

$x - 8 = 0$

Step 2

Add $8$ to both sides of the equation.

$x = 8$

Step 3

The domain is all values of $x$ that make the expression defined.

Interval Notation:

$(- \infty, 8) \cup (8, \infty)$

Set-Builder Notation:

${x | x \neq 8}$

Step 4