Find the Equation Using Point-Slope Formula (1,40) , (3,110)

$(1, 40)$ , $(3, 110)$

Step 1

Find the slope of the line between $(1, 40)$ and $(3, 110)$ using $m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ , which is the change of $y$ over the change of $x$ .

Slope is equal to the change in $y$ over the change in $x$ , or rise over run.

$m = \frac{change in y}{change in x}$

The change in $x$ is equal to the difference in x-coordinates (also called run), and the change in $y$ is equal to the difference in y-coordinates (also called rise).

$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$

Substitute in the values of $x$ and $y$ into the equation to find the slope.

$m = \frac{110 - (40)}{3 - (1)}$

Simplify.

Simplify the numerator.

Multiply $- 1$ by $40$ .

$m = \frac{110 - 40}{3 - (1)}$

Subtract $40$ from $110$ .

$m = \frac{70}{3 - (1)}$

Simplify the denominator.

Multiply $- 1$ by $1$ .

$m = \frac{70}{3 - 1}$

Subtract $1$ from $3$ .

$m = \frac{70}{2}$

Divide $70$ by $2$ .

$m = 35$

Step 2

Use the slope $35$ and a given point $(1, 40)$ to substitute for $x_{1}$ and $y_{1}$ in the point-slope form $y - y_{1} = m (x - x_{1})$ , which is derived from the slope equation $m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ .

$y - (40) = 35 \cdot (x - (1))$

Step 3

Simplify the equation and keep it in point-slope form.

$y - 40 = 35 \cdot (x - 1)$

Step 4

Solve for $y$ .

Simplify $35 \cdot (x - 1)$ .

Rewrite.

$y - 40 = 0 + 0 + 35 \cdot (x - 1)$

Simplify by adding zeros.

$y - 40 = 35 \cdot (x - 1)$

Apply the distributive property.

$y - 40 = 35 x + 35 \cdot - 1$

Multiply $35$ by $- 1$ .

$y - 40 = 35 x - 35$

Move all terms not containing $y$ to the right side of the equation.

Add $40$ to both sides of the equation.

$y = 35 x - 35 + 40$

Add $- 35$ and $40$ .

$y = 35 x + 5$

Step 5

List the equation in different forms.

Slope-intercept form:

$y = 35 x + 5$

Point-slope form:

$y - 40 = 35 \cdot (x - 1)$

Step 6

Find the Equation Using Point-Slope Formula (1,40) , (3,110)

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