Find the Exact Value 10/3+2/7-1/2

$\frac{10}{3} + \frac{2}{7} - \frac{1}{2}$

Find the common denominator.

Multiply $\frac{10}{3}$ by $\frac{14}{14}$ .

$\frac{10}{3} \cdot \frac{14}{14} + \frac{2}{7} - \frac{1}{2}$

Multiply $\frac{10}{3}$ by $\frac{14}{14}$ .

$\frac{10 \cdot 14}{3 \cdot 14} + \frac{2}{7} - \frac{1}{2}$

Multiply $\frac{2}{7}$ by $\frac{6}{6}$ .

$\frac{10 \cdot 14}{3 \cdot 14} + \frac{2}{7} \cdot \frac{6}{6} - \frac{1}{2}$

Multiply $\frac{2}{7}$ by $\frac{6}{6}$ .

$\frac{10 \cdot 14}{3 \cdot 14} + \frac{2 \cdot 6}{7 \cdot 6} - \frac{1}{2}$

Multiply $\frac{1}{2}$ by $\frac{21}{21}$ .

$\frac{10 \cdot 14}{3 \cdot 14} + \frac{2 \cdot 6}{7 \cdot 6} - (\frac{1}{2} \cdot \frac{21}{21})$

Multiply $\frac{1}{2}$ by $\frac{21}{21}$ .

$\frac{10 \cdot 14}{3 \cdot 14} + \frac{2 \cdot 6}{7 \cdot 6} - \frac{21}{2 \cdot 21}$

Multiply $3$ by $14$ .

$\frac{10 \cdot 14}{42} + \frac{2 \cdot 6}{7 \cdot 6} - \frac{21}{2 \cdot 21}$

Reorder the factors of $7 \cdot 6$ .

$\frac{10 \cdot 14}{42} + \frac{2 \cdot 6}{6 \cdot 7} - \frac{21}{2 \cdot 21}$

Multiply $6$ by $7$ .

$\frac{10 \cdot 14}{42} + \frac{2 \cdot 6}{42} - \frac{21}{2 \cdot 21}$

Multiply $2$ by $21$ .

$\frac{10 \cdot 14}{42} + \frac{2 \cdot 6}{42} - \frac{21}{42}$

Combine the numerators over the common denominator.

$\frac{10 \cdot 14 + 2 \cdot 6 - 21}{42}$

Simplify each term.

Multiply $10$ by $14$ .

$\frac{140 + 2 \cdot 6 - 21}{42}$

Multiply $2$ by $6$ .

$\frac{140 + 12 - 21}{42}$

Simplify by adding and subtracting.

Add $140$ and $12$ .

$\frac{152 - 21}{42}$

Subtract $21$ from $152$ .

$\frac{131}{42}$

The result can be shown in multiple forms.

Exact Form:

$\frac{131}{42}$

Decimal Form:

$3.11904761 \dots$

Mixed Number Form:

$3 \frac{5}{42}$