Find the Exact Value ((8)(-7)(6))/((-4)(-2)(-3))

$\frac{(8) (- 7) (6)}{(- 4) (- 2) (- 3)}$

Step 1

Reduce the expression by cancelling the common factors.

Cancel the common factor of $8$ and $- 4$ .

Factor $4$ out of $(8) (- 7) (6)$ .

$\frac{4 ((2) \cdot - 7 \cdot 6)}{(- 4) (- 2) (- 3)}$

Cancel the common factors.

Factor $4$ out of $(- 4) (- 2) (- 3)$ .

$\frac{4 ((2) \cdot - 7 \cdot 6)}{4 (- - 2 \cdot - 3)}$

Cancel the common factor.

$\frac{4 ((2) \cdot - 7 \cdot 6)}{4 (- - 2 \cdot - 3)}$

Rewrite the expression.

$\frac{(2) \cdot - 7 \cdot 6}{- - 2 \cdot - 3}$

Cancel the common factor of $2$ and $- 2$ .

Factor $2$ out of $(2) \cdot - 7 \cdot 6$ .

$\frac{2 (- 7 \cdot 6)}{- - 2 \cdot - 3}$

Cancel the common factors.

Factor $2$ out of $- - 2 \cdot - 3$ .

$\frac{2 (- 7 \cdot 6)}{2 (- - 1 \cdot - 3)}$

Cancel the common factor.

$\frac{2 (- 7 \cdot 6)}{2 (- - 1 \cdot - 3)}$

Rewrite the expression.

$\frac{- 7 \cdot 6}{- - 1 \cdot - 3}$

Cancel the common factor of $6$ and $- 3$ .

Factor $3$ out of $- 7 \cdot 6$ .

$\frac{3 (- 7 \cdot 2)}{- - 1 \cdot - 3}$

Cancel the common factors.

Factor $3$ out of $- - 1 \cdot - 3$ .

$\frac{3 (- 7 \cdot 2)}{3 (- - 1 \cdot - 1)}$

Cancel the common factor.

$\frac{3 (- 7 \cdot 2)}{3 (- - 1 \cdot - 1)}$

Rewrite the expression.

$\frac{- 7 \cdot 2}{- - 1 \cdot - 1}$

Multiply $- 7$ by $2$ .

$\frac{- 14}{- - 1 \cdot - 1}$

Step 2

Simplify the denominator.

Multiply $- 1$ by $- 1$ .

$\frac{- 14}{1 \cdot - 1}$

Multiply $- 1$ by $1$ .

$\frac{- 14}{- 1}$

Step 3

Divide $- 14$ by $- 1$ .

$14$