Find the Exact Value i^(20+1)

$i^{20 + 1}$

Add $20$ and $1$ .

$i^{21}$

Rewrite $i^{21}$ as ${(i^{4})}^{5} i$ .

Factor out $i^{20}$ .

$i^{20} i$

Rewrite $i^{20}$ as ${(i^{4})}^{5}$ .

${(i^{4})}^{5} i$

${(i^{4})}^{5} i$

Rewrite $i^{4}$ as $1$ .

Rewrite $i^{4}$ as ${(i^{2})}^{2}$ .

${({(i^{2})}^{2})}^{5} i$

Rewrite $i^{2}$ as $- 1$ .

${({(- 1)}^{2})}^{5} i$

Raise $- 1$ to the power of $2$ .

$1^{5} i$

$1^{5} i$

One to any power is one.

$1 i$

Multiply $i$ by $1$ .

$i$

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