Find the Inverse square root of 6x-12

$\sqrt{6 x - 12}$

Step 1

Interchange the variables.

$x = \sqrt{6 y - 12}$

Step 2

Solve for $y$ .

Rewrite the equation as $\sqrt{6 y - 12} = x$ .

$\sqrt{6 y - 12} = x$

To remove the radical on the left side of the equation, square both sides of the equation.

${\sqrt{6 y - 12}}^{2} = x^{2}$

Simplify each side of the equation.

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{6 y - 12}$ as ${(6 y - 12)}^{\frac{1}{2}}$ .

${({(6 y - 12)}^{\frac{1}{2}})}^{2} = x^{2}$

Simplify the left side.

Simplify ${({(6 y - 12)}^{\frac{1}{2}})}^{2}$ .

Multiply the exponents in ${({(6 y - 12)}^{\frac{1}{2}})}^{2}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

${(6 y - 12)}^{\frac{1}{2} \cdot 2} = x^{2}$

Cancel the common factor of $2$ .

Cancel the common factor.

${(6 y - 12)}^{\frac{1}{2} \cdot 2} = x^{2}$

Rewrite the expression.

${(6 y - 12)}^{1} = x^{2}$

Simplify.

$6 y - 12 = x^{2}$

Solve for $y$ .

Add $12$ to both sides of the equation.

$6 y = x^{2} + 12$

Divide each term in $6 y = x^{2} + 12$ by $6$ and simplify.

Divide each term in $6 y = x^{2} + 12$ by $6$ .

$\frac{6 y}{6} = \frac{x^{2}}{6} + \frac{12}{6}$

Simplify the left side.

Cancel the common factor of $6$ .

Cancel the common factor.

$\frac{6 y}{6} = \frac{x^{2}}{6} + \frac{12}{6}$

Divide $y$ by $1$ .

$y = \frac{x^{2}}{6} + \frac{12}{6}$

Simplify the right side.

Divide $12$ by $6$ .

$y = \frac{x^{2}}{6} + 2$

Step 3

Replace $y$ with $f^{- 1} (x)$ to show the final answer.

$f^{- 1} (x) = \frac{x^{2}}{6} + 2$

Step 4

Verify if $f^{- 1} (x) = \frac{x^{2}}{6} + 2$ is the inverse of $f (x) = \sqrt{6 x - 12}$ .

To verify the inverse, check if $f^{- 1} (f (x)) = x$ and $f (f^{- 1} (x)) = x$ .

Evaluate $f^{- 1} (f (x))$ .

Set up the composite result function.

$f^{- 1} (f (x))$

Evaluate $f^{- 1} (\sqrt{6 x - 12})$ by substituting in the value of $f$ into $f^{- 1}$ .

$f^{- 1} (\sqrt{6 x - 12}) = \frac{{(\sqrt{6 x - 12})}^{2}}{6} + 2$

Simplify each term.

Simplify the numerator.

Factor $6$ out of $6 x - 12$ .

Factor $6$ out of $6 x$ .

$f^{- 1} (\sqrt{6 x - 12}) = \frac{{\sqrt{6 (x) - 12}}^{2}}{6} + 2$

Factor $6$ out of $- 12$ .

$f^{- 1} (\sqrt{6 x - 12}) = \frac{{\sqrt{6 x + 6 \cdot - 2}}^{2}}{6} + 2$

Factor $6$ out of $6 x + 6 \cdot - 2$ .

$f^{- 1} (\sqrt{6 x - 12}) = \frac{{\sqrt{6 (x - 2)}}^{2}}{6} + 2$

Rewrite ${\sqrt{6 (x - 2)}}^{2}$ as $6 (x - 2)$ .

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{6 (x - 2)}$ as ${(6 (x - 2))}^{\frac{1}{2}}$ .

$f^{- 1} (\sqrt{6 x - 12}) = \frac{{({(6 (x - 2))}^{\frac{1}{2}})}^{2}}{6} + 2$

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$f^{- 1} (\sqrt{6 x - 12}) = \frac{{(6 (x - 2))}^{\frac{1}{2} \cdot 2}}{6} + 2$

Combine $\frac{1}{2}$ and $2$ .

$f^{- 1} (\sqrt{6 x - 12}) = \frac{{(6 (x - 2))}^{\frac{2}{2}}}{6} + 2$

Cancel the common factor of $2$ .

Cancel the common factor.

$f^{- 1} (\sqrt{6 x - 12}) = \frac{{(6 (x - 2))}^{\frac{2}{2}}}{6} + 2$

Rewrite the expression.

$f^{- 1} (\sqrt{6 x - 12}) = \frac{6 (x - 2)}{6} + 2$

Simplify.

$f^{- 1} (\sqrt{6 x - 12}) = \frac{6 (x - 2)}{6} + 2$

Apply the distributive property.

$f^{- 1} (\sqrt{6 x - 12}) = \frac{6 x + 6 \cdot - 2}{6} + 2$

Multiply $6$ by $- 2$ .

$f^{- 1} (\sqrt{6 x - 12}) = \frac{6 x - 12}{6} + 2$

Factor $6$ out of $6 x - 12$ .

Factor $6$ out of $6 x$ .

$f^{- 1} (\sqrt{6 x - 12}) = \frac{6 (x) - 12}{6} + 2$

Factor $6$ out of $- 12$ .

$f^{- 1} (\sqrt{6 x - 12}) = \frac{6 x + 6 \cdot - 2}{6} + 2$

Factor $6$ out of $6 x + 6 \cdot - 2$ .

$f^{- 1} (\sqrt{6 x - 12}) = \frac{6 (x - 2)}{6} + 2$

Cancel the common factor of $6$ .

Cancel the common factor.

$f^{- 1} (\sqrt{6 x - 12}) = \frac{6 (x - 2)}{6} + 2$

Divide $x - 2$ by $1$ .

$f^{- 1} (\sqrt{6 x - 12}) = x - 2 + 2$

Combine the opposite terms in $x - 2 + 2$ .

Add $- 2$ and $2$ .

$f^{- 1} (\sqrt{6 x - 12}) = x + 0$

Add $x$ and $0$ .

$f^{- 1} (\sqrt{6 x - 12}) = x$

Evaluate $f (f^{- 1} (x))$ .

Set up the composite result function.

$f (f^{- 1} (x))$

Evaluate $f (\frac{x^{2}}{6} + 2)$ by substituting in the value of $f^{- 1}$ into $f$ .

$f (\frac{x^{2}}{6} + 2) = \sqrt{6 (\frac{x^{2}}{6} + 2) - 12}$

Factor $6$ out of $6 (\frac{x^{2}}{6} + 2) - 12$ .

Factor $6$ out of $- 12$ .

$f (\frac{x^{2}}{6} + 2) = \sqrt{6 (\frac{x^{2}}{6} + 2) + 6 \cdot - 2}$

Factor $6$ out of $6 (\frac{x^{2}}{6} + 2) + 6 \cdot - 2$ .

$f (\frac{x^{2}}{6} + 2) = \sqrt{6 (\frac{x^{2}}{6} + 2 - 2)}$

Simplify by subtracting numbers.

Subtract $2$ from $2$ .

$f (\frac{x^{2}}{6} + 2) = \sqrt{6 (\frac{x^{2}}{6} + 0)}$

Add $\frac{x^{2}}{6}$ and $0$ .

$f (\frac{x^{2}}{6} + 2) = \sqrt{6 (\frac{x^{2}}{6})}$

Combine $6$ and $\frac{x^{2}}{6}$ .

$f (\frac{x^{2}}{6} + 2) = \sqrt{\frac{6 x^{2}}{6}}$

Reduce the expression by cancelling the common factors.

Reduce the expression $\frac{6 x^{2}}{6}$ by cancelling the common factors.

Cancel the common factor.

$f (\frac{x^{2}}{6} + 2) = \sqrt{\frac{6 x^{2}}{6}}$

Rewrite the expression.

$f (\frac{x^{2}}{6} + 2) = \sqrt{\frac{x^{2}}{1}}$

Divide $x^{2}$ by $1$ .

$f (\frac{x^{2}}{6} + 2) = \sqrt{x^{2}}$

Pull terms out from under the radical, assuming positive real numbers.

$f (\frac{x^{2}}{6} + 2) = x$

Since $f^{- 1} (f (x)) = x$ and $f (f^{- 1} (x)) = x$ , then $f^{- 1} (x) = \frac{x^{2}}{6} + 2$ is the inverse of $f (x) = \sqrt{6 x - 12}$ .

$f^{- 1} (x) = \frac{x^{2}}{6} + 2$

Find the Inverse square root of 6x-12

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