Find the Exact Value log base 4 of 64+ log base 2 of 32- log base 3 of 27

$\log_{4} (64) + \log_{2} (32) - \log_{3} (27)$

Simplify each term.

Logarithm base $4$ of $64$ is $3$ .

$3 + \log_{2} (32) - \log_{3} (27)$

Logarithm base $2$ of $32$ is $5$ .

$3 + 5 - \log_{3} (27)$

Logarithm base $3$ of $27$ is $3$ .

$3 + 5 - 1 \cdot 3$

Multiply $- 1$ by $3$ .

$3 + 5 - 3$

Simplify by adding and subtracting.

Add $3$ and $5$ .

$8 - 3$

Subtract $3$ from $8$ .

$5$