Find the Exact Value square root of -936+ square root of -2,600

$\sqrt{- 936} + \sqrt{- 2600}$

Simplify each term.

Rewrite $- 936$ as $- 1 (936)$ .

$\sqrt{- 1 (936)} + \sqrt{- 2600}$

Rewrite $\sqrt{- 1 (936)}$ as $\sqrt{- 1} \cdot \sqrt{936}$ .

$\sqrt{- 1} \cdot \sqrt{936} + \sqrt{- 2600}$

Rewrite $\sqrt{- 1}$ as $i$ .

$i \cdot \sqrt{936} + \sqrt{- 2600}$

Rewrite $936$ as $6^{2} \cdot 26$ .

Factor $36$ out of $936$ .

$i \cdot \sqrt{36 (26)} + \sqrt{- 2600}$

Rewrite $36$ as $6^{2}$ .

$i \cdot \sqrt{6^{2} \cdot 26} + \sqrt{- 2600}$

Pull terms out from under the radical.

$i \cdot (6 \sqrt{26}) + \sqrt{- 2600}$

Move $6$ to the left of $i$ .

$6 \cdot i \sqrt{26} + \sqrt{- 2600}$

Rewrite $- 2600$ as $- 1 (2600)$ .

$6 i \sqrt{26} + \sqrt{- 1 (2600)}$

Rewrite $\sqrt{- 1 (2600)}$ as $\sqrt{- 1} \cdot \sqrt{2600}$ .

$6 i \sqrt{26} + \sqrt{- 1} \cdot \sqrt{2600}$

Rewrite $\sqrt{- 1}$ as $i$ .

$6 i \sqrt{26} + i \cdot \sqrt{2600}$

Rewrite $2600$ as $10^{2} \cdot 26$ .

Factor $100$ out of $2600$ .

$6 i \sqrt{26} + i \cdot \sqrt{100 (26)}$

Rewrite $100$ as $10^{2}$ .

$6 i \sqrt{26} + i \cdot \sqrt{10^{2} \cdot 26}$

Pull terms out from under the radical.

$6 i \sqrt{26} + i \cdot (10 \sqrt{26})$

Move $10$ to the left of $i$ .

$6 i \sqrt{26} + 10 i \sqrt{26}$

Add $6 i \sqrt{26}$ and $10 i \sqrt{26}$ .

$16 i \sqrt{26}$