Find the Excluded Values (5x-10)/(x^2-36)*(4x+24)/(x^2+5x-14)

$\frac{5 x - 10}{x^{2} - 36} \cdot \frac{4 x + 24}{x^{2} + 5 x - 14}$

Set the denominator in $\frac{5 x - 10}{x^{2} - 36}$ equal to $0$ to find where the expression is undefined.

$x^{2} - 36 = 0$

Solve for $x$ .

Add $36$ to both sides of the equation.

$x^{2} = 36$

Take the square root of both sides of the equation to eliminate the exponent on the left side.

$x = \pm \sqrt{36}$

Simplify $\pm \sqrt{36}$ .

Rewrite $36$ as $6^{2}$ .

$x = \pm \sqrt{6^{2}}$

Pull terms out from under the radical, assuming positive real numbers.

$x = \pm 6$

The complete solution is the result of both the positive and negative portions of the solution.

First, use the positive value of the $\pm$ to find the first solution.

$x = 6$

Next, use the negative value of the $\pm$ to find the second solution.

$x = - 6$

The complete solution is the result of both the positive and negative portions of the solution.

$x = 6, - 6$

Set the denominator in $\frac{4 x + 24}{x^{2} + 5 x - 14}$ equal to $0$ to find where the expression is undefined.

$x^{2} + 5 x - 14 = 0$

Solve for $x$ .

Factor $x^{2} + 5 x - 14$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $- 14$ and whose sum is $5$ .

$- 2, 7$

Write the factored form using these integers.

$(x - 2) (x + 7) = 0$

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x - 2 = 0$

$x + 7 = 0$

Set $x - 2$ equal to $0$ and solve for $x$ .

Set $x - 2$ equal to $0$ .

$x - 2 = 0$

Add $2$ to both sides of the equation.

$x = 2$

Set $x + 7$ equal to $0$ and solve for $x$ .

Set $x + 7$ equal to $0$ .

$x + 7 = 0$

Subtract $7$ from both sides of the equation.

$x = - 7$

The final solution is all the values that make $(x - 2) (x + 7) = 0$ true.

$x = 2, - 7$

The equation is undefined where the denominator equals $0$ , the argument of a square root is less than $0$ , or the argument of a logarithm is less than or equal to $0$ .

$x = - 7, x = - 6, x = 2, x = 6$

Find the Excluded Values (5x-10)/(x^2-36)*(4x+24)/(x^2+5x-14)

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