Find the First Term a_n=((n+2)!)/(n+2)

$a_{n} = \frac{(n + 2)!}{n + 2}$

Substitute in the value of $n$ to find the $n$ th term.

$a_{1} = \frac{((1) + 2)!}{(1) + 2}$

Simplify the numerator.

Add $1$ and $2$ .

$a_{1} = \frac{(3)!}{1 + 2}$

Expand $(3)!$ to $3 \cdot 2 \cdot 1$ .

$a_{1} = \frac{3 \cdot 2 \cdot 1}{1 + 2}$

Simplify.

Multiply $3$ by $2$ .

$a_{1} = \frac{6 \cdot 1}{1 + 2}$

Multiply $6$ by $1$ .

$a_{1} = \frac{6}{1 + 2}$

Simplify the expression.

Add $1$ and $2$ .

$a_{1} = \frac{6}{3}$

Divide $6$ by $3$ .

$a_{1} = 2$