Find the Focus y^2-8x+10y+9=0

$y^{2} - 8 x + 10 y + 9 = 0$

Step 1

Rewrite the equation in vertex form.

Isolate $x$ to the left side of the equation.

Move all terms not containing $x$ to the right side of the equation.

Subtract $y^{2}$ from both sides of the equation.

$- 8 x + 10 y + 9 = - y^{2}$

Subtract $10 y$ from both sides of the equation.

$- 8 x + 9 = - y^{2} - 10 y$

Subtract $9$ from both sides of the equation.

$- 8 x = - y^{2} - 10 y - 9$

Divide each term in $- 8 x = - y^{2} - 10 y - 9$ by $- 8$ and simplify.

Divide each term in $- 8 x = - y^{2} - 10 y - 9$ by $- 8$ .

$\frac{- 8 x}{- 8} = \frac{- y^{2}}{- 8} + \frac{- 10 y}{- 8} + \frac{- 9}{- 8}$

Simplify the left side.

Cancel the common factor of $- 8$ .

Cancel the common factor.

$\frac{- 8 x}{- 8} = \frac{- y^{2}}{- 8} + \frac{- 10 y}{- 8} + \frac{- 9}{- 8}$

Divide $x$ by $1$ .

$x = \frac{- y^{2}}{- 8} + \frac{- 10 y}{- 8} + \frac{- 9}{- 8}$

Simplify the right side.

Simplify each term.

Dividing two negative values results in a positive value.

$x = \frac{y^{2}}{8} + \frac{- 10 y}{- 8} + \frac{- 9}{- 8}$

Cancel the common factor of $- 10$ and $- 8$ .

Factor $- 2$ out of $- 10 y$ .

$x = \frac{y^{2}}{8} + \frac{- 2 (5 y)}{- 8} + \frac{- 9}{- 8}$

Cancel the common factors.

Factor $- 2$ out of $- 8$ .

$x = \frac{y^{2}}{8} + \frac{- 2 (5 y)}{- 2 (4)} + \frac{- 9}{- 8}$

Cancel the common factor.

$x = \frac{y^{2}}{8} + \frac{- 2 (5 y)}{- 2 \cdot 4} + \frac{- 9}{- 8}$

Rewrite the expression.

$x = \frac{y^{2}}{8} + \frac{5 y}{4} + \frac{- 9}{- 8}$

Dividing two negative values results in a positive value.

$x = \frac{y^{2}}{8} + \frac{5 y}{4} + \frac{9}{8}$

Complete the square for $\frac{y^{2}}{8} + \frac{5 y}{4} + \frac{9}{8}$ .

Use the form $a x^{2} + b x + c$ , to find the values of $a$ , $b$ , and $c$ .

$a = \frac{1}{8}$

$b = \frac{5}{4}$

$c = \frac{9}{8}$

Consider the vertex form of a parabola.

$a {(x + d)}^{2} + e$

Find the value of $d$ using the formula $d = \frac{b}{2 a}$ .

Substitute the values of $a$ and $b$ into the formula $d = \frac{b}{2 a}$ .

$d = \frac{\frac{5}{4}}{2 (\frac{1}{8})}$

Simplify the right side.

Multiply the numerator by the reciprocal of the denominator.

$d = \frac{5}{4} \cdot \frac{1}{2 (\frac{1}{8})}$

Combine $2$ and $\frac{1}{8}$ .

$d = \frac{5}{4} \cdot \frac{1}{\frac{2}{8}}$

Cancel the common factor of $2$ and $8$ .

Factor $2$ out of $2$ .

$d = \frac{5}{4} \cdot \frac{1}{\frac{2 (1)}{8}}$

Cancel the common factors.

Factor $2$ out of $8$ .

$d = \frac{5}{4} \cdot \frac{1}{\frac{2 \cdot 1}{2 \cdot 4}}$

Cancel the common factor.

$d = \frac{5}{4} \cdot \frac{1}{\frac{2 \cdot 1}{2 \cdot 4}}$

Rewrite the expression.

$d = \frac{5}{4} \cdot \frac{1}{\frac{1}{4}}$

Multiply the numerator by the reciprocal of the denominator.

$d = \frac{5}{4} (1 \cdot 4)$

Cancel the common factor of $4$ .

Factor $4$ out of $1 \cdot 4$ .

$d = \frac{5}{4} (4 \cdot 1)$

Cancel the common factor.

$d = \frac{5}{4} (4 \cdot 1)$

Rewrite the expression.

$d = 5$

Find the value of $e$ using the formula $e = c - \frac{b^{2}}{4 a}$ .

Substitute the values of $c$ , $b$ and $a$ into the formula $e = c - \frac{b^{2}}{4 a}$ .

$e = \frac{9}{8} - \frac{{(\frac{5}{4})}^{2}}{4 (\frac{1}{8})}$

Simplify the right side.

Simplify each term.

Simplify the numerator.

Apply the product rule to $\frac{5}{4}$ .

$e = \frac{9}{8} - \frac{\frac{5^{2}}{4^{2}}}{4 (\frac{1}{8})}$

Raise $5$ to the power of $2$ .

$e = \frac{9}{8} - \frac{\frac{25}{4^{2}}}{4 (\frac{1}{8})}$

Raise $4$ to the power of $2$ .

$e = \frac{9}{8} - \frac{\frac{25}{16}}{4 (\frac{1}{8})}$

Combine $4$ and $\frac{1}{8}$ .

$e = \frac{9}{8} - \frac{\frac{25}{16}}{\frac{4}{8}}$

Cancel the common factor of $4$ and $8$ .

Factor $4$ out of $4$ .

$e = \frac{9}{8} - \frac{\frac{25}{16}}{\frac{4 (1)}{8}}$

Cancel the common factors.

Factor $4$ out of $8$ .

$e = \frac{9}{8} - \frac{\frac{25}{16}}{\frac{4 \cdot 1}{4 \cdot 2}}$

Cancel the common factor.

$e = \frac{9}{8} - \frac{\frac{25}{16}}{\frac{4 \cdot 1}{4 \cdot 2}}$

Rewrite the expression.

$e = \frac{9}{8} - \frac{\frac{25}{16}}{\frac{1}{2}}$

Multiply the numerator by the reciprocal of the denominator.

$e = \frac{9}{8} - (\frac{25}{16} \cdot 2)$

Cancel the common factor of $2$ .

Factor $2$ out of $16$ .

$e = \frac{9}{8} - (\frac{25}{2 (8)} \cdot 2)$

Cancel the common factor.

$e = \frac{9}{8} - (\frac{25}{2 \cdot 8} \cdot 2)$

Rewrite the expression.

$e = \frac{9}{8} - \frac{25}{8}$

Combine the numerators over the common denominator.

$e = \frac{9 - 25}{8}$

Subtract $25$ from $9$ .

$e = \frac{- 16}{8}$

Divide $- 16$ by $8$ .

$e = - 2$

Substitute the values of $a$ , $d$ , and $e$ into the vertex form $\frac{1}{8} {(y + 5)}^{2} - 2$ .

$\frac{1}{8} {(y + 5)}^{2} - 2$

Set $x$ equal to the new right side.

$x = \frac{1}{8} \cdot {(y + 5)}^{2} - 2$

Step 2

Use the vertex form, $x = a {(y - k)}^{2} + h$ , to determine the values of $a$ , $h$ , and $k$ .

$a = \frac{1}{8}$

$h = - 2$

$k = - 5$

Step 3

Find the vertex $(h, k)$ .

$(- 2, - 5)$

Step 4

Find $p$ , the distance from the vertex to the focus.

Find the distance from the vertex to a focus of the parabola by using the following formula.

$\frac{1}{4 a}$

Substitute the value of $a$ into the formula.

$\frac{1}{4 \cdot \frac{1}{8}}$

Simplify.

Combine $4$ and $\frac{1}{8}$ .

$\frac{1}{\frac{4}{8}}$

Cancel the common factor of $4$ and $8$ .

Factor $4$ out of $4$ .

$\frac{1}{\frac{4 (1)}{8}}$

Cancel the common factors.

Factor $4$ out of $8$ .

$\frac{1}{\frac{4 \cdot 1}{4 \cdot 2}}$

Cancel the common factor.

$\frac{1}{\frac{4 \cdot 1}{4 \cdot 2}}$

Rewrite the expression.

$\frac{1}{\frac{1}{2}}$

Multiply the numerator by the reciprocal of the denominator.

$1 \cdot 2$

Multiply $2$ by $1$ .

$2$

Step 5

Find the focus.

The focus of a parabola can be found by adding $p$ to the x-coordinate $h$ if the parabola opens left or right.

$(h + p, k)$

Substitute the known values of $h$ , $p$ , and $k$ into the formula and simplify.

$(0, - 5)$

Step 6

Find the Focus y^2-8x+10y+9=0

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