Find the Roots (Zeros) y=x^3+3x^2+1

$y = x^{3} + 3 x^{2} + 1$

Step 1

Set $x^{3} + 3 x^{2} + 1$ equal to $0$ .

$x^{3} + 3 x^{2} + 1 = 0$

Step 2

Graph each side of the equation. The solution is the x-value of the point of intersection.

$x \approx - 3.1038034$

Step 3