Find the Holes in the Graph f(x)=(x^2-5x-6)/(x-2)

$f (x) = \frac{x^{2} - 5 x - 6}{x - 2}$

Factor $x^{2} - 5 x - 6$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $- 6$ and whose sum is $- 5$ .

$- 6, 1$

Write the factored form using these integers.

$f (x) = \frac{(x - 6) (x + 1)}{x - 2}$

Since no factors can be removed from the denominator, there are no holes in the graph.

No holes

Find the Holes in the Graph f(x)=(x^2-5x-6)/(x-2)

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