Find the Mass of 1 Mole Mg(NO_3)_2

$M g {(N O_{3})}_{2}$

Step 1

To find the mass of $1$ mole of $M g {(N O_{3})}_{2}$ look up the atomic mass of each element and multiply it by the number of atoms contained in each element in the molecule.

mass of $1$ mole of $M g {(N O_{3})}_{2}$ $=$ $(mass of Mg)$ + $2 (mass of N)$ + $6 (mass of O)$

Step 2

Fill in the atomic masses from the periodic table.

mass of $1$ mole of $M g {(N O_{3})}_{2}$ $=$ $(24.30999946)$ + $2 (14.01000022)$ + $6 (16)$

Step 3

Simplify the result.

Simplify each term.

Multiply $2$ by $14.01000022$ .

mass of $1$ mole of $M g {(N O_{3})}_{2} = 24.30999946 + 28.02000045 + 6 (16) g$

Multiply $6$ by $16$ .

mass of $1$ mole of $M g {(N O_{3})}_{2} = 24.30999946 + 28.02000045 + 96 g$

Simplify by adding numbers.

Add $24.30999946$ and $28.02000045$ .

mass of $1$ mole of $M g {(N O_{3})}_{2} = 52.32999992 + 96 g$

Add $52.32999992$ and $96$ .

mass of $1$ mole of $M g {(N O_{3})}_{2} = 148.32999992 g$

Find the Mass of 1 Mole Mg(NO_3)_2

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