Find the Mass Percentages Ba(OH)_2

$B a {(O H)}_{2}$

Step 1

To find the mass of $1$ mole of $B a {(O H)}_{2}$ look up the atomic mass of each element and multiply it by the number of atoms contained in each element in the molecule.

mass of $1$ mole of $B a {(O H)}_{2}$ $=$ $(mass of Ba)$ + $2 (mass of O)$ + $2 (mass of H)$

Step 2

Fill in the atomic masses from the periodic table.

mass of $1$ mole of $B a {(O H)}_{2}$ $=$ $(137.33000183)$ + $2 (16)$ + $2 (1.00999999)$

Step 3

Simplify the result.

Simplify each term.

Multiply $2$ by $16$ .

mass of $1$ mole of $B a {(O H)}_{2} = 137.33000183 + 32 + 2 (1.00999999) g$

Multiply $2$ by $1.00999999$ .

mass of $1$ mole of $B a {(O H)}_{2} = 137.33000183 + 32 + 2.01999998 g$

Simplify by adding numbers.

Add $137.33000183$ and $32$ .

mass of $1$ mole of $B a {(O H)}_{2} = 169.33000183 + 2.01999998 g$

Add $169.33000183$ and $2.01999998$ .

mass of $1$ mole of $B a {(O H)}_{2} = 171.35000181 g$

Step 4

Find the mass percentage of $B a$ .

The mass composition percentage is the mass of $B a$ divided by the mass of the entire molecule converted to a percentage.

Mass percentage of $B a = \frac{137.33}{171.35000181} \cdot 100$

Divide $137.33$ by $171.35000181$ .

$0.80145899 \cdot 100$

Multiply $0.80145899$ by $100$ .

$80.14589935$

Set the number as a percent.

Mass percentage of $B a = 80.14589935 %$

Step 5

Find the mass percentage of $O$ .

The mass composition percentage is the mass of $O$ divided by the mass of the entire molecule converted to a percentage.

Mass percentage of $O = \frac{32}{171.35000181} \cdot 100$

Divide $32$ by $171.35000181$ .

$0.18675225 \cdot 100$

Multiply $0.18675225$ by $100$ .

$18.67522594$

Set the number as a percent.

Mass percentage of $O = 18.67522594 %$

Step 6

Find the mass percentage of $H$ .

The mass composition percentage is the mass of $H$ divided by the mass of the entire molecule converted to a percentage.

Mass percentage of $H = \frac{2.02}{171.35000181} \cdot 100$

Divide $2.02$ by $171.35000181$ .

$0.01178873 \cdot 100$

Multiply $0.01178873$ by $100$ .

$1.17887363$

Set the number as a percent.

Mass percentage of $H = 1.17887363 %$

Step 7

Find the mass percentage of each element in the molecule.

Mass percentage of $B a = 80.14589935 %$

Mass percentage of $O = 18.67522594 %$

Mass percentage of $H = 1.17887363 %$

Find the Mass Percentages Ba(OH)_2

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