Find the Maximum/Minimum Value 625-16x^2

$625 - 16 x^{2}$

Step 1

The maximum of a quadratic function occurs at $x = - \frac{b}{2 a}$ . If $a$ is negative, the maximum value of the function is $f (- \frac{b}{2 a})$ .

$f_{max}$ $x = a x^{2} + b x + c$ occurs at $x = - \frac{b}{2 a}$

Step 2

Find the value of $x = - \frac{b}{2 a}$ .

Substitute in the values of $a$ and $b$ .

$x = - \frac{0}{2 (- 16)}$

Remove parentheses.

$x = - \frac{0}{2 (- 16)}$

Simplify $- \frac{0}{2 (- 16)}$ .

Cancel the common factor of $0$ and $2$ .

Factor $2$ out of $0$ .

$x = - \frac{2 (0)}{2 (- 16)}$

Cancel the common factors.

Cancel the common factor.

$x = - \frac{2 \cdot 0}{2 \cdot - 16}$

Rewrite the expression.

$x = - \frac{0}{- 16}$

Cancel the common factor of $0$ and $- 16$ .

Factor $16$ out of $0$ .

$x = - \frac{16 (0)}{- 16}$

Move the negative one from the denominator of $\frac{0}{- 1}$ .

$x = - (- 1 \cdot 0)$

Rewrite $- 1 \cdot 0$ as $- 0$ .

$x = - - 0$

Multiply $- - 0$ .

Multiply $- 1$ by $0$ .

$x = - 0$

Multiply $- 1$ by $0$ .

$x = 0$

Step 3

Evaluate $f (0)$ .

Replace the variable $x$ with $0$ in the expression.

$f (0) = 625 - 16 {(0)}^{2}$

Simplify the result.

Simplify each term.

Raising $0$ to any positive power yields $0$ .

$f (0) = 625 - 16 \cdot 0$

Multiply $- 16$ by $0$ .

$f (0) = 625 + 0$

Add $625$ and $0$ .

$f (0) = 625$

The final answer is $625$ .

$625$

Step 4

Use the $x$ and $y$ values to find where the maximum occurs.

$(0, 625)$

Step 5

Find the Maximum/Minimum Value 625-16x^2

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